Remove New line from XML Data in XSLT

Hi,

In some case where we are sending data to a file and their may case data contain EOL itself which will be a data issue to other system which process file.

In such cases we have to handle EOL in XSLT only.

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0" xmlns:ns0="http://xmlns.oracle.com/pcbpel/adapter/db/top/Load_PROJ_SCM_V_Data"
                xmlns:oraxsl="http://www.oracle.com/XSL/Transform/java"
                ">
  <oracle-xsl-mapper:schema>
    <!--SPECIFICATION OF MAP SOURCES AND TARGETS, DO NOT MODIFY.-->
    <oracle-xsl-mapper:mapSources>
      <oracle-xsl-mapper:source type="WSDL">
     
      </oracle-xsl-mapper:target>
    </oracle-xsl-mapper:mapTargets>
    <!--GENERATED BY ORACLE XSL MAPPER 12.1.3.0.0(XSLT Build 140529.0700.0211) AT [TUE MAY 21 03:13:57 EDT 2019].-->
  </oracle-xsl-mapper:schema>
  <!--User Editing allowed BELOW this line - DO NOT DELETE THIS LINE-->



 <!-- this is called an identity template -->
  <xsl:template match="/">
    <xsl:apply-templates/>
  </xsl:template>
  <xsl:template match="*">
    <xsl:copy>
      <xsl:for-each select="@*">
        <xsl:attribute name="{name()}">
          <xsl:value-of select="normalize-space()"/>
        </xsl:attribute>
      </xsl:for-each>
      <xsl:apply-templates/>
    </xsl:copy>
  </xsl:template>
  <xsl:template match="text()">
    <xsl:value-of select="normalize-space()"/>
  </xsl:template>
</xsl:stylesheet>